Var
a: array[1..10] of integer;
i, max, imax: integer;
begin
for i:=1 to 10 do
readln(a[i]);
max := 0;
for i:=1 to 10 do
if (a[i] > max) and (a[i] > 4) and (a[i] < 9) then
begin
max := a[i];
imax := i;
end;
writeln(imax);
end.
256 × 1024 =262144 килобайт
262145 × 1024 = 268435456 байт
268435456 × 8 = 2147483648 бит
1) 65536/16 = 4096
2) 16*32 = 512
1000*512=512000 битов
# python 3
n = int(input())
print(sum(i**2 for i in range(n + 1)))