2CH4=C2H2+3H2
3C2H2=C6H6
C6H6+Cl2=C6H5Cl+HCl
C6H5Cl+NaOH=C6H5OH+NaCl
C6H5OH+3Br2=C6H2OHBr3+3HBr
б) CH4+Cl2=CH3Cl+HCl
2CH3Cl+2Na=C2H6+2NaCl
C2H6+Cl2=C2H5Cl+HCl
C2H5Cl+CH3Cl+2Na=C3H8+2NaCl
C3H8+Cl2=C3H7Cl+HCl
2C3H7Cl+2Na=C6H14+2NaCl
C6H14=C6H6+4H2
C6H6+Cl2=C6H5Cl+HCl
C6H5Cl+NaOH=C6H5OH+NaCl
C6H5OH+3HNO3=C6H2(NO2)3OH+3H2O
Опять таки,1 моль оксида - это 102 г,которые содержат 6,02*10 в 23 степени молекул,а
Ответ:
Объяснение:
1) Ca + H₂ = CaH₂
2) CaH₂ + 2H₂O = Ca(OH)₂ + 2H₂
↑
3) Ca(OH)₂ + К₂CO₃ = 2КOH + CaCO₃
4) CaCO₃ + 2HCl = CaCl₂ + H₂O + CO₂
↑
5) CaH₂ + O₂ = CaO + H₂O
6) Ca(OH)₂ = CaO + H₂O
7) 3CaCl₂ + 2Na₃PO₄ = Ca₃(PO₄)₂↓ + 6NaCl
3Ca²⁺ + 6Cl⁻ + 6Na⁺ + 2PO₄³⁻ = Ca₃(PO₄)₂↓ + 6Na⁺ + 6Cl⁻
3Ca²⁺ + 2PO₄³⁻ = Ca₃(PO₄)₂↓
Fe=56* 3=168
Fe3o4=232
M(Fe)/M(Fe3O4)*100%=168/232*100%=72,4%