3Ca(H2PO4)2+ 12KOH= Ca3(PO4)2 + 4K3PO4 + 6H2O
1. H3PO4 Wелемента =n×Ar/Mречовини
Mреч=1×3+31+16×4=98
W(H)= 3×1/98=0.03
W(O)=4×16/98=0.65
W(P)= 31×1/98=0.31
2.Al2(SO4)3
Mреч=27×2+32×3+16×12=342
W(Al)=27×2/323=0.16
W(O)=16×12/343=0.56
W(S)=32×3/342=0.28
3.NaOH
Mреч= 23+1+16=40
W(Na)=23×1/40=0.575
W(H)=1×1/40=0.025
W(O)=16×1/40=0.4
Ответ:113,3 литр
Объяснение:
100000*0,80742*96/(100000*0,80742+a*0,9982)=40
7751232=3229680+39,92a
a=113,3 литр
C+O2=CO2;
<span>Ca(OH)2 + CO2 = CaCO3 + H2O;</span>
<span><span>Cu + Cl2 = CuCl2</span></span>
2HNO2 + 2HI -> 2NO + I2 + 2H2O
N(+3) +1e =N(+2) 2 ок-ль, в-ие
2I(-) -2e = I2(0) 1 в-ль, ок-ие