+2. Щелочно-земельный металл (по группе).
C6H5OH+3Br2= C6H2Br3OH+3HBr
6,62/331=0,02 моль этого осадка
0.02*94=1,88 г фенола
1,88/20=9,4% фенола и 90,6% бензола
N2 + 3H2 = 2NH<span>3
</span>2NH3 +<span> H</span>2SO4 =<span> (NH</span>4)2SO<span>4
</span>(NH4)2SO4 +<span> BaCl</span>2 = 2NH4<span>Cl </span>+<span> BaSO</span><span>4
</span>NH4<span>Cl </span>+<span> NaOH </span>=<span> NaCl </span>+<span> NH</span>3 +<span> H</span>2<span>O
</span>NH3 +<span> HNO</span>3 =<span> NH</span>4NO<span>3</span>
<span>Ca3(PO4)2+6AgNo3=3ca(NO3)2+2Ag3PO4</span>