!!!!!!!!!!!!!!!!!!!!!!!!!
log2x+6log2^2x+9log2^3x=14
log2x+6*1\2log2x+9*1\3log2x=14
log2x+3log2x+3log2x=14
log2x+log2x^3+log2x^3=14
log2(x*x^3*x^3)=14
log2x^7=14
x=
Если 1/(5х+8) = 1/3,
то 5х+8 = 3,
х = (3-8)/5 = -1.
Ответ: -1.
Расстояние АС 33 см(AC=AB=BC, 15+18=33 см)