<span>2 × (1 / 10)² – 2 / 5 × 3 / 10</span>= 2*1/10*1/10-2/5*3/10=1/5*1/10-2/5*3/10=1/50-6/50=-5/50=-1/10
8^4=2^12
2^12/2^-3
2^12*2^-(-)3=2^15
(x-y)²=x²-2xy+y²
(3a+8b)²=9a²+48ab+64b²
(4a²-5b³)²=16a^4-40a²b³+25b^6
(n-m)(n+m)=n²-m²
(5x+7y)(5x-7y)=25x²-49y²
(3a²-2b²)(3a²+2b²)=9a^4-4b^4
(4x+3)²-24x=16x²+24x+9-24x=16x²+9
√15
2√3=√12
3=√9
√3
наибольшее √15
Ответ:1) √15.
Q=mc(t-p)
t-p=Q/mc
<span>p=t-Q/mc</span>