Y -2 0 2 4 6 ..........................................................................
Решение
<span>sin(p/2-a)cos(p+a)/ctg(p+a)tg(3p/2-a) =
= [cosa * (- cosa)] / [ctga * ctga] = - cos</span>²a / (cos²a/sin²a) = - sin²a
3sin²x-2sinxcosx=1
3sin²x-2sinxcosx=sin²x+cos²x
2sin²x-2sinxcosx-cos²x=0|:sin²x
ctg²x+2ctgx-2=0
D=4+8=12; √D=2√3
ctgx=(-1±√3)/2
x=arcctg(-1±√3)/2+πn
2) 1+sin²x=2sinxcosx
2sin²x-2sinx*cosx+cos²x=0|:cos²x
2tg²x-2tgx+1=0