Cos(3x - π/6) - Cos(x + π/4) = 0 (применим формулу разности косинусов)
-2Sin(2x+π/12)*Sin(x - π/3) = 0
Sin(2x+π/12) = 0 или <span>Sin(x - π/3) = 0
2x + </span>π/12 = πn , n ∈Z x - π/3 = πk, k ∈Z
2x = nπ - π/12, n ∈Z x = πk + π/3, k ∈Z
x = nπ/2 - π/24 , n ∈Z
(5-t)(-t-5)-(4+t)² = (-t)²-25-(16+8t+t²) = (-t)²-25-16-8t-t² = - 41 - 8t
Решение смотри в приложении