=8x/8x+1 + 3/-(8x-1) - 64x^2+1/(8x-1)*(8x+1)=
=8x*(8x-1)-398x+1)-(64x^2+1)/(8x-1)*(8x+1)=
64x^2-8x-24x-3-64x^2-1/(8x-1)*8(x+1/8)=
=-32x-4/(8x-1)*8(x+1/8)=-32(x-4/-32)/(8x-1)*8(x+1/8)=
-4(x+1/8)/(8x-1)*(x+1/8) сократим дробь на x+1/8
=-4/8x-1
ответ:1
F ' (x)=3x^2-12x-63<0
3x^2-12x-63=0
Д=100
X1=7 или X2= -3
X принадлежит (-бесконечность; -3)