1/х:1/х^4=1/x*x^4=x^4/x=x^3 При х=-2 ответ будет -8. Думаю, что так.
100-q^2 = (10-q)(10+q)
196p^2-r^2 = (14p-r)(14p+r)
25x^2 - 289y^2 = (5x-17y)(5x+17y)
a^2b^4 - 9c^2 = (ab^2-3c)(ab^2+3c)
(m-1)^2 -121 = (m-1+11)(m-1-11)
x^2 - 144 = 0
x^2 = 144 /:V
x1 = 12 i x2=-12
3(x+4y)
a³(2a³+1)
4(x+4y)
a(3a+1)
y(x)=1/√(x-1)
y'(x)=(1/√(x-1))'=(1'*√(x-1)-1*(√(x-1))')/(√(x-1))²=(0-(1/(2*√(x-1))/(x-1)=-1/(2*√(x-1)³).