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Решение
2cos ( 2x + пи/3) <= 1
cos ( 2x + пи/3) <= 1/2
пи/3 +2пи*n <= 2x + пи/3<= 5пи/3+2пи*n
2пи*n <= 2x <= 4пи/3+2пи*n
<span>пи*n <= x <= 2пи/3+пи*n</span>
8п/7<10п/7 (8/7=1,14;10/7=1,42)
2/(22/22)=2
(2+2+2)/2+2=5
222*2+2=446