1)4Al + 3O2<span> = 2Al</span>2O<span>3
2)</span>Al + 6HNO3(конц) = Al(NO3)3<span> + 3NO</span>2<span> + 3H</span>2<span>O
3)</span>2Al + 3F2<span> = 2AlF</span><span>3
</span> 2Al + 3S = Al2S<span>3
</span>4Al + 3С = Al4С<span>3
4)</span>8Al + 15H2SO4(конц) = 4Al2(SO4)3<span> + 3H</span>2S + 12H2<span>O
5)</span><span>Al+3NaCl = AlCl3 + 3Na Al + 3NaOH = Al(OH)3 + 3Na </span><span>
6)</span>6NaOH + 2Al = 2Na3AlO3<span> + 3H</span>2
5 электронов на внешнем энергетическом уровне.
M(S) = 32
M(Ag2S) = 108 * 2 + 32 = 248
<span>m(S) </span>= 32 * 124 : 248 = 16 г
Ответ: 16 г
4 Na + O2--- 2 Na2O
Na2O +2 HCl ----2 NaCl + H2O
Na2O + H2O--- 2 NaOH
3 NaOH + H3PO4----- Na3PO4 + 3 H2O
тогда так