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2Cos5x Cosx - Cos5x = 0
Cos5x(2Cosx -1) = 0
Cos5x = 0 или 2Cosx -1 = 0
5x = π/2 + πk , k ∈Z Cosx = 1/2
x = π/10 + πk/5, k ∈Z x = +-arcCos1/2 + 2πn , n ∈Z
x = +-π/3 + 2πn , n ∈Z
⅔у=9 | умножим обе части на 3
А²=8²+6²
а²=64+36=100
а=10 дм
ответ: диагональ равна 10 дм
A= 2 + √2 b= 2 - √2
a+b= 2+√2+2-√2=4
a*b=(2+√2)(2-√2)=4-2=2