T^2=1.21
t= корень из 1.21
t1 = 1.1
t2 = -1.1
Ответ: 1.1 ; -1.1
<span>t^2=63
t= корень из 63
t1 = 3 корня из 7
t2 = -3 корня из 7
Ответ:</span> 3 корня из 7; <span>-3 корня из 7</span>
А)а6 = а1+5d = 23;
a11 = a1+10d = 48;
a11-a6 = 5d = 25;
d=5;
подставим в а6: 23 = a1 + 5*5=a1+25;
a1=23-25=-2.
б)a4=a1+3d=4;
a12=a1+11d=12;
a12-a4=8d=8;
8d=8 => d=1;
a1+3d=4 => a1 = 4 -3*1;
a1=4-3=1;
a1=1
<span><span>(<span><span>a2</span>−<span>b2</span>+ab−2</span>)</span><span>(<span><span>a2</span>−<span>b2</span>−ab−2</span>)</span>−<span><span>(<span><span>a2</span>−<span>b2</span>−2</span>)</span>2</span>=</span>Возведение в степень:<span><span>(<span><span>a2</span>−<span>b2</span>+ab−2</span>)</span><span>(<span><span>a2</span>−<span>b2</span>−ab−2</span>)</span>−<span>(<span><span>a4</span>−2<span>a2</span><span>b2</span>−4<span>a2</span>+<span>b4</span>+4<span>b2</span>+4</span>)</span>=</span>Раскрытие скобок:<span><span><span>a4</span>+<span>a2</span><span>(<span>−1</span>)</span><span>b2</span>+<span>a3</span><span>(<span>−1</span>)</span>b+<span>a2</span><span>(<span>−2</span>)</span>−<span>b2</span><span>a2</span>+<span>b4</span>+<span>b3</span>a+2<span>b2</span>+<span>a3</span>b+a<span>b3</span><span>(<span>−1</span>)</span></span><span>+<span>a2</span><span>b2</span><span>(<span>−1</span>)</span>+ab<span>(<span>−2</span>)</span>−2<span>a2</span>+2<span>b2</span>+2ab+4−<span>a4</span>+2<span>a2</span><span>b2</span>+4<span>a2</span>−<span>b4</span>−4<span>b2</span>−4=</span></span><span><span>a2</span><span>(<span>−1</span>)</span><span>b2</span>−<span>b2</span><span>a2</span>+<span>b3</span>a+a<span>b3</span><span>(<span>−1</span>)</span>+<span>a2</span><span>b2</span>=</span><span>−<span>a2</span><span>b2</span>−<span>b2</span><span>a2</span>+<span>b3</span>a−a<span>b3</span>+<span>a2</span><span>b2</span>=</span>−a2b2
Ответ:
1) имеет будет 1 , второе тож имеет (лень считать)
3)не имеет 4 )не имеет
Объяснение:
надо все домножить на 3, чтобы избавиться от знаменателя получится...