Решить уравнение:
х^2(<span>х+1)-(х+2)(2х-3)=х^2(х-1)
x^3 + x - 3x + 3 x - 4x + 6 = x^3 -x
</span><span>x^3 + x - 4x + 6 = x^3 -x
</span>x^3 + x - 4x - <span>x^3 + x</span> = - 6
x - 4x <span>+ x = - 6
</span>2x - 4x = - 6
-2x = - 6
x = - 6 / - 2
x = 3
3•(-8)+2у+30=0;
2у=-30+24;
2у=-4;
у=-4:2;
у=-2
12h*17m<span>+25mh=204mh+25mh=229mh</span>