(1+ y)*(y+1)=1
(1+y)²=1
1+2y+y²=1
1+2y+y²-1=0
y²+2y=0
y(y+2)=0
<u>y₁=0 </u>
y+2=0
<u>y₂= -2</u>
ОТВЕТ: <u>y₁=0 </u>, <u> y₂= -2</u>
x^2-8x>0,