<em>cos^2(3x-п/6)=3/4</em>
<em>cos(3x-п/6)=+-sqrt(3)/2</em>
<em>[3x-п/6=п/6+2пn; n e Z;</em>
<em>[3x-п/6=-п/6+2пn; n e Z;</em>
<em> </em>
<em>[3x=п/3+2пn; n e Z;</em>
<em>[3x=2пn; n e Z;</em>
<em>Ответ: </em>
[x=п/9+(2пn)/3; n e Z;
[x=(2пn)/3; n e Z;
<span>2sin^2x+2sin^2x*cos^2x/sin^2x+1</span>
<span><span>2sin^2x+2cos^2x+1</span></span>
<span><span>ответ 2sin^2x+2cos^2x+1</span></span>
<span><span>можно еще дальше решить:</span></span>
<span><span>2sin^2+2cos^2x=1*2=2</span></span>
<span><span>2+1=3</span></span>