NH3 + HNO3 = NH4NO3.........
Первое:
<span><span>2</span><span>Na</span><span>O</span><span>H</span></span><span> + </span><span><span>H</span><span>2</span><span>S</span><span>O</span><span>4</span></span><span> = </span><span>Na</span><span>2</span><span>S</span><span>O</span><span>4</span><span> + </span><span>2</span><span>H</span><span>2</span><span>O</span>
<span><span>2</span><span>Na</span>+<span> + </span><span>2</span><span>O</span><span>H</span>−<span> + </span><span>2</span><span>H</span>+<span> + </span><span>S</span><span>O</span><span>4</span>2−<span> = </span><span>2</span><span>Na</span>+<span> + </span><span>S</span><span>O</span><span>4</span>2−<span> + </span><span>2</span><span>H</span><span>2</span><span>O</span></span>
<span><span><span>2</span><span>O</span><span>H</span>−<span> + </span><span>2</span><span>H</span>+<span> = </span><span>2</span><span>H</span><span>2</span><span>O</span></span></span>
<span><span><span>Второе:</span></span></span>
<span><span><span>HNO3 + K2CO3 = HK2 + CO3NO3</span></span></span>
<span><span><span><span>HNO</span>3<span> + K</span>2<span>CO</span>3<span> = HK</span>2<span> + CO</span>3<span>NO</span>3</span></span></span>
Третье:
2HCl+MgО=MgCL2+H2O
2H(+)+2Cl(-)+MgО=Mg(+2)+2CL(-)+H2O
2H(+)+MgО=Mg(+2)+H2O
Четвёртое:
<span><span>3</span><span>K</span><span>O</span><span>H</span></span><span> + </span><span><span>Fe</span>(<span>N</span><span>O</span><span>3</span>)<span>3</span></span><span> = </span><span>3</span><span>K</span><span>N</span><span>O</span><span>3</span><span> + </span><span>Fe</span><span>(<span>O</span><span>H</span>)</span><span>3</span>
<span><span>3</span><span>K</span>+<span> + </span><span>3</span><span>O</span><span>H</span>−<span> + </span><span>Fe</span>3+<span> + </span><span>3</span><span>N</span><span>O</span><span>3</span>−<span> = </span><span>3</span><span>K</span>+<span> + </span><span>Fe</span><span>(<span>O</span><span>H</span>)</span><span>3</span><span>+ </span><span>3</span><span>N</span><span>O</span><span>3</span>−</span>
<span><span>3</span><span>O</span><span>H</span>−<span> + </span><span>Fe</span>3+<span> = </span><span>Fe</span><span>(<span>O</span><span>H</span>)</span><span>3</span><span>+</span></span>
Пятое хз каак..
Шестое:
ZnSO4 +K3PO4=ZnSO4<span> +KOH</span>
W(Zn)=0,4757
w(O)=0,2328
w(Ca)=1-{w(Zn)+w(O)}=0,2915
CaxZnyOz
молярная масса вещества
M(CaxZnyOz)=40x+65y+16z
массовые доли элементов
w(Ca)=xM(Ca)/M(CaxZnyOz)
w(Zn)=yM(Zn)/M(CaxZnyOz)
w(O)=zM(O)/M(CaxZnyOz)
система уравнений
40x/{40x+65y+16z}=0,2915
65y/{40x+65y+16z}=0,4757
16z/{40x+65y+16z}=0,2328
решаем...
x=1
y=1
z=2
ZnO + CaO (t)= CaZnO₂ цинкат кальция
1) В исходном воздухе объемная доля азота примерно равна 0,78 (а 0,75 - это массовая доля)
2) Возьмем 100 л воздуха, значит азота в нем 0,78 * 100 = 78 л
3) Если мы прибавим к 100 л воздуха Х л азота, то азота в нем будет (78+Х) л, а объем смеси станет (100+Х) л, поэтому можем записать:
(78+Х)/(100+Х) = 0,85
78 + Х = 85+0,85Х
0,15Х = 7
Х = 46,67
Значит воздух и азот должны находиться в соотношении:
100 частей воздуха : 46,67 частей азота