C4H8+HCl=C4H9Cl (н.у)
..........................................
CH4 + 2O2 → CO2 + 2H2O
67,2 / 1 = X / 2
X = 67,2 × 2 / 1 = 134,4 л
A)2Na + 2H₂O = 2NaOH + H₂↑
2Na⁰ + 2H₂O = 2Na⁺ +2OH⁻ + H₂↑
2Na⁰ - 1e= 2Na⁺
2H⁺ + 1 e = H₂⁰
б) 6Na + N₂ = 2Na₃N
6Na⁰ - 1e = 6Na⁺
N₂° + 3 e = 2N⁻³
M(C6H12O6)=180г/моль
N(C6H12O6)=1,3*6,02*10²³(молекул
m(C6H12O6)=1,3*180=234г