2KL+Br2⇒2KBr+l2↓
Реакция взаимодействия иодида и калия и брома
C4H10=(кат. AlCl3)=H3C-CH(CH3)-CH3
H3C-CH(CH3)-CH3+Br2 = H3C-CBr(CH3)-CH3
H3C-CBr(CH3)-CH3+H2 =(кат)= H3C-CH(CH3)-CH3
H3C-CH(CH3)-CH3 =(t,кат)= H2C=C(Ch3)-Ch3
H2C=C(Ch3)-Ch3 + h2o = H3C-C(Oh)(Ch3)-Ch3