Ответ: а)Na2SO4
Na2SO4 = (23*2)+32+(16*4) = 142
wNA2 = 46:142 = <span>0.3239 = 32,39%
wS = 32:142 = </span>0.2254 = 22,54%
wO4 = 64:142 = <span>0.4507 = 45,07 %</span>
N=0,1 (m/M=n)
2,4/48=x/1127
x=56,35 кДж
5,6/22,4=0,25 моль
2,8/22,4=0,125 моль
0,25+0,125 = 0,375 моль