A)x(x+3)=0 x=0 u x= -3 b) y(3y+1)=0 y=0 u y= - 1\3 v) 5z^2-3z=0 z(5z-3)=0 z=0 u z= 3\5
(xa+xb)+(6a+6b)= x(a+b)+6(a+b)=(x+6)(a+b)
Y=7x²+6x-1
7x²+6x-1=0,D=36+28=64, √D=√64=8
x1=(-6+8)/14=2/14=1/7
x2=(-6-8)/14=-14/14=-1
y(1/7)=0,y(-1)=0
<span>(4,9-х):4=0,6</span>