MgSO4 + Ba(NO3)2 = Mg(NO3)2 + BaSO4
Mg(2+) + SO4(2-) + Ba(2+) + 2NO3(-) = Mg(2+) + 2NO3(-) + BaSO4
Ba(2+) + SO4(2-) = BaSO4.
Випаде білий, нерозчинний у кислотах розчин.
Ответ:
дано
m(CH3COOH) = 64 g
m(C2H5OH) = 10 g
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m(CH3COOC2H5)-?
M(CH3COOH) = 60 g/mol
n(CH3COOH) = m(CH3COOH) / M(CH3COOH) = 64 / 60 = 1.07 mol
M(C2H5OH) = 46 g/mol
n(C2H5OH) = m(C2H5OH) / M(C2H5OH) = 10 / 46 = 0.22 mol
n(CH3COOH) > n(C2H5OH)
M(CH3COOC2H5) = 88 g/mol
CH3COOH+C2H5OH-->CH3COOC2H5+H2O
n(C2H5OH) = n(CH3COOC2H5) = 0.22 mol
m(CH3COOC2H5) = n(CH3COOC2H5) * M(CH3COOC2H5)
m(CH3COOC2H5) = 0.22 * 88 = 19.36 g
ответ 19.36 г
Объяснение:
Ответ:
Fe2O3 +3H2SO4⇒ Fe2(SO4)3 + 3H2O
Fe2(SO4)3 +6NaOH⇒2Fe(OH)3 + 3Na2SO4
Fe(OH)3 + 3HCl⇒FeCl3+ 3H2O