1) q=b2/b1=1/sqrt(2)
S=b1/(1-q)=sqrt(2)/(1-1/sqrt(2))=sqrt(2)/((sqrt(2)-1)/sqrt(2))=2/(sqrt(2)-1)=2(sqrt(2)+1)=2sqrt(2)+2
2)b5=b1*q^4
sqrt(2)/16=b1*(1/2)^4
sqrt(2)/16=b1/16
b1=sqrt(2)
S=sqrt(2)/(1-1/2)=2sqrt(2)
В первом сосуде 35 литров, а во втором сосуде 28
5x-3y=7|*(-2)
7x-6y=8
-10x+6y=-14
7x-6y=8
___________
-3x=(-6):(-3)
x=2
5*2-3y=7 10-3y=7 -3y=(-3) y=1
= 4cos(3π/2-π/3)-tg(π/2+π/4)= -4sin(π/3)-ctg(π/4) = -2√3-1