cos2x+sin²x = 0,75
cos²x - sin²x + sin²x = 0.75
cos²x = 0.75
cosx = ±√0.75 = ±0.5√3
1) cosx = -0.5√3
x₁ = 5π/6 + 2πn
x₂ = -5π/6 + 2πn
n =1 x₁ = (2 + 5/6) π x∉[π; 5π/2]
x₂ = (2- 5/6) π = 7π/6 x∈[π; 5π/2]
n =2 x₁ = (4 + 5/6) π x∉[π; 5π/2]
x₂ = (4- 5/6) π x∉[π; 5π/2]
2) cosx = 0.5√3
x₁ = π/6 + 2πn
x₂ = -π/6 + 2πn
n =1 x₁ = (2 + 1/6) π = 13π/6 x∈[π; 5π/2]
x₂ = (2 - 1/6) π = 11π/6 x∈[π; 5π/2]
n =2 x₁ = (4 + 1/6) π x∉[π; 5π/2]
x₂ = (4- 1/6) π x∉[π; 5π/2]
Ответ: x = 7π/6; 11π/6; 13π/6
Ну если брать полное число пи, то 3^π > 3^3,14
А если брать что π ~ 3,14, то 3^π=3^3,14
1/7,2/7,3/7,4/7,5/7,6/7,7/7 ; 4/5,4/6,...
Получается
1,1x+68.7 , при x=0.3 будет 69,03
1)-7/11*1 5/17=-7/11*22/17=-14/17
2)-14/17:0,75=-14/17:3/4=-14/17*4/3=-56/51=-1 5/51