Дано:
m(KOH)=7,4г
HCl
m(KCl)-?
7,4г. Хг
KOH + HCl = KCl + HOH
m=M*n. m=M*n
n=1моль. n=1моль
М=Мr. М=Мr
Mr(KOH)= Mr(KCl)=39+
=39+16+1=56 +35,5=74,5
M=56г/моль.M=74,5г/моль
m=56г. m=74,5г
7,4/56=Х/74,5
Х=(7,4*74,5)/56=10(г)
SO3 + 2KOH = K2SO4 + H2O
n(SO3) = 8.0/80=0.1моль
n(SO3):n(K2SO4) 1:1
n(K2SO4) = 0.1моль
m(K2SO4) = 0.1*174=17,4г
w=17,4/174*100% = 10%
...........
1) CH2-CH-CH3
| |
F Br
2)<span>CH3-CH-CH-CH2-CH3
</span> | |
CH3 CH3
3) CH3 CH3
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<span>CH3-C-CH2-C-CH2-CH2-CH2-CH3</span>
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CH3 CH3
4Fes2 +11O2 = 2Fe2O3+8SO2
2SO2 + O2 = SO3 *4. 8SO2 + 8O2= 8SO3
SO3 + H2O= H2SO4 *8. 8SO3 + 8H2O = 8H2SO4
4FeS2--->8SO2--->8SO3--->8H2SO4
4Fes2--->8H2SO. Fes2--->2H2SO4
n(H2SO4) = 130 / 98 = 1.32 моль
n(FeS2) = 1/2n(H2SO4) = 0.66 моль
m(FeS2 ) = 0,66*120 = 79.6г
W(примесей) =(100 - 79.6)*100% / 100 = 20,4%