1)5z+8-(11z-6)=2
5z+8-11z+6=2
-6z+14=2
-6z=2-14
-6z=-12
z=2
2)9t-14-(5-6t)=6
9t-14-5+6t=6
15t-19=6
15t=19+6
15t=25
t=25/15=5/3
1) (x-5)(x+5)= x²-25
2) (8+y)(y-8)= y²-64
3) (10-k)(k+10)= 100-k²
4) (a+2/4b)(a-2/4b)= a²-4/16b= a²-1/4b
5) (4/9x-y)(y+4/9x)= 16/81x²-y²
6) (4/15n-m)(m+4/15n)= 16/225n²-m²
7) (9x-5y)(9x+5y)= 81x²-25y²
8) (-4a+3b)(3b+4a)= (3b-4a)(3b+4a)= 9b²-16a²
9) (13k-2d)(2d+13k)= 169k²-4d²
10) (5/4c+3/7d)(3/7d-5/4c)= 9/49d²-25/16c²
11) (1/3x-3y)(3y+1/3x)= 1/9x²-9y²
12) (1/5a+1/9b)(1/9b-1/5a) 1/81b²-1/25a²
25х - х² = 0
-x² + 25x = 0
а= - 1 ; b = 25 ; с= 0
D = 25² - 4*(-1)*0 = 25² = 625
x₁ = ( - 25 - 25)/(2*(-1)) = - 50/(-2) = 25
x₂ = (-25+25)/( 2 *(-1)) = 0
3x² - 48 = 0
a=3 ; b=0 ; с= - 48
D = 0 - 4*3*(-48) = 576 = 24²
x₁ = -24/(2*3) = - 24/6 = - 4
x₂ = 24/(2*3) = 24/6 = 4
27х - х² = 0
-х² + 27х = 0
а= - 1 ; b = 27 ; с =0
D = 27² - 4*(-1)*0 = 27² = 729
x₁ = ( -27 - 27)/(2*(-1)) = -54/ -2 = 27
x₂ = (-27 + 27) / ( 2*(-1)) = 0
4x² - 36 = 0
a= 4 ; b = 0 ; с = -36
D = - 4*4*(-36) = 576 = 24²
x₁ = -24/(2*4) =- 24/8 = - 3
х₂ = 24/(2*4) = 24/8 = 3
Ответ:
Объяснение:а) x=0 тогда y=6, x=1 тогда y=9, черти
Б) -x=0 тогда y 2, -x=-1 тогда y=1
Черти и в какой точке они пересекутся будет ответ