Sin^3-cos^3=(sin-cos)(sin^2+sincos+cos^2)=0.5 (1+sincos)
Потом сам там альфа поставь tj04
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x₁ = - 4 x₂ = - 3
x² + bx + c = 0
c = x₁ * x₂ = (- 4 ) * ( - 3) = 12
b = - (x₁ + x₂) = - ( - 4 - 3) = 7
Ответ : x² + 7x + 12 = 0