Решение
y = x⁴ - 12x²
y` = 4x³ - 24x
y` = 0
4x³ - 24x = 0
4x*(x² - 6) = 0
x₁ = 0
x² - 6 = 0
x² = 6
x₂ = - √6
x₃ = √6
<span>4 sin^2x cos^2x+4 cos^4x-4 cos^2x+ 1 =</span><span> 4cos^2x(</span><span><span>sin^2x +</span>cos^2x) - 4cos^2x+ 1=
=</span> 4cos^2x <span>- 4cos^2x+ 1=</span> 1
(3/7)^(3x+1)=(3/7)^(3-5x)
3x+1=3-5x
3x+5x=3-1
8x=2
x=1/4