W(соли)=m(соли)*100% /m(p-pa)=
=184*100/460=40%
<span>2Li + 3H</span>2<span>SO</span>4<span> (конц.) = 2LiHSO</span>4<span> + SO</span>2<span>↑ + 2H</span>2<span>O</span>
<span><span>2H</span>2<span>O + 2Li = 2LiOH + H</span>2 <span>↑</span></span>
<span><span><span>2Li + Cl </span>2<span> = 2LiCl
Тут наверно ошибка не <span>iOH, а L<span>iOH
<span>Li</span>2<span>O + H</span>2<span>O = 2LiOH</span>
<span>LiOH + HCl (разб.) = LiCl + H</span>2<span>O</span>
</span></span></span></span></span>
Изобутиламин, бутиламин, этиламин
ZnO + 2HNO3 = Zn(NO3)2 + H2O
6.3/126 = x/189;
x = (6.3*189)/126 = 9.45 грамм