Кислород, магний, ванадий, ртуть, иттрий.
CaCO3 + SiO2 →CO2 + CaSiO3
m=30 m= 29
n = 0.3 моль n=0.25 моль m=5 kg
w=5/30 = 16.7 %
Ответ: 16.7%
СH3Cl + 2Na + ClCH3 -> CH3-CH3 + 2NaCl
CH3-CH3 + Cl2 -> CH3-CH2Cl + HCl (hv)
CH3-CH3 + HNO3 -> CH3-CH2-NO2 + H2O (p,t)
m(Cu(OH)2) = 64 + (16 *2) + (1*2) = 98 г/моль
W(Cu) = 64/98 = 65.3%
W(O) = 32/98 = 32.6%
W(H) = 2/98 = 2%
C4H9COOH+C3H7OH=C4H9COOC3H7+H2O