<span><u>lim(x→1) [(∛x-1) / (√x-1)]</u></span>
x^1/3-1 = (x^1/6)²-1² =(x^1/6-1)(x^1/6+1)
x^1/2-1 = (x^1/6)³-1³ = (x^1/6-1)(x^2/6+x^1/6+1)
(x^1/6-1)(x^1/6+1):(x^1/6-1)(x^1/3+x^1/6+1)=
=(x^1/6+1)/(x^1/3+x^1/6+1)
lim(x^1/6+1)/(x^1/3+x^1/6+1) = (1+1)/(1+1+1) = 2/3
x->1
7/5-5/6=42/30-25/30=17/30
<span>3/4 = 9 / x+8
3(х+8)=4×9
3х+24=36
3х=36-24
3х=12
х=4
</span>
108108|297
891 |364
1900
1782
1 1 88
1 1 88
0
Ответ:364
150 дм в квадрате так что ли .......