Ответ:
Объяснение:
1)
IACI²=17²-8²=289-64=225
IACI=15
sinα=8/17
cosα=IACI/17=15/17
tgα=8/IACI=8/15
sinβ=IACI/17=15/17
cosβ=8/17
tgβ=IACI/8=15/8
2)
IABI²=21²+20²=441-400=841
IABI=29
sinα=21/IABI=21/29
cosα=20/IABI=20/19
tgα=21/20
sinβ=20/IABI=20/29
cosβ=21/IABI=21/29
tgβ=20/21
3)
IABI²=1²+2²=1+4=5
IAB=√5
sinα=1/IABI=1/√5=√5/5
cosα=2/IABI=2/V5=2V5/5
tgα=1/2
sinβ=2/AB=2/√5=2√5/5
cosβ=1/AB=1/√5=√5/5
tgβ=2/1=2
4)
IBCI²=25²-24²=265-576=49
IBCI=7
sinα=IBCI/25=7/25
cosα=24/25
tgα=IBCI/24=7/24
sinβ=24/25
cosβ=IBCI/25=7/25
tgβ=24/IBCI=24/7
√2^4·5²=√2²·2²·5²=√2²·10²=2·10=20
8x^12-27=(2x^4-3)*(4x^8+6x^4+9).
<span>0,4c^2d(−4c^2−cd−d)=-1.6c^4d-0.4c^3d^2-0.4c^2d^2</span>