Фотография………………. б.б…… .
X-5<8/(x+2) ОДЗ: x+2≠0 x≠-2
x-5-(8/(x+2))<0
(x-5)*(x+2)-8<0
x²-5x+2x-10-8<0
x²-3x-18<0
x²-3x-18=0 D=81
x₁=6 x₂=-3
(x-6)(x+3)<0
-∞____+____-3____-____6____+_____+∞
x∈(-3;6).
Согласно ОДЗ:
x∈(-3;-2)U(-2;6).
{5x-2y=11{4x-y=4 5x-2y=11y=4x-4 5x-2(4x-4)=11 5x-8x+8=11 -3x+3 X=-1 <span>y=-4-4=-8</span>