Дано
m(CxHy)= 8 g
V(CO2)= 13.44 L
m(H2O)= 10.8 g
m(CxHy) = m(He) / 2
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CxHy-?
CxHy+O2-->CO2+H2O
n(C) = n(CO2) = m/M = 13.44/44 = 0.3 mol
n(H) = 2n(H2O)=2*(m/M) = 2*10.8 / 18 = 1.2 mol
n(C): n(H) = 0.3 : 1.2 = 1 :4
CH4
m(He) = m(CH4) / 2 = 8/2= 4 g
ответ МЕТАН
N2+o2=2NO; NO+O2=2NO2 (NO+O3=NO2+O2); 2NO2+H2=hNO2+HNO3; NH3+HCL=NH4CL...
NH4CL+KNH2=2NH3+KCl;
4NH3+5O2=4NO+6H2O; 2NO+O2=2NO2; H2+2NO2=HNO2+HNO3; 4Mg+10HNO3=4MG(NO3)2+N2O+5H2O;