По моему в условии ошибка:
1) (2+p)
2)(6t-(t-p)) * (6t + (t-p))=(5t+p) * (7t - p)
3)25a^2 - 81b^2 - 25a^2=81b^2=81*0,01=0,81
Х 0 1 2
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у 0 -2 -4
Решение
Log3(x)+logx(3)=3
x > 0, x ≠ 1
Log₃(x) + log₃ (3) / log₃ (<span>x) = 3
log</span>²₃ (x) - 3*log₃ (x) + 1 = 0
<span>log₃ (x) = t
</span>t² - 3t + 1 = 0
D = 9 - 4*1*1 = 5
t₁ = (3 - √5)/2
t₁ = <span>(3 + √5)/2
log</span>₃ (x) = <span>(3 - √5)/2
</span>x₁ = 3^(<span>(3 - √5)/2
</span>x₂ = 3^(<span>(3 + √5)/2</span>