S=b1/(1-q);
b2=b1*g;
b1*q=-90 (1);
b5=b1*q^4;
b1*q^4=80/3 (2);
разделим (2) на (1):
b1*q^4/b1*q=80/3 : (-90);
q^3=-8/27;
q=-2/3;
-90=b1*(-2/3);
b1=-90 : (-2/3)=135;
S=135 : (1-(-2/3))=135 : 5/3=81;
Ответ: 81
<span>(4х+1)(x-3)=x^2+4х-3</span>
x³-y³=26
x²+xy+y²=13
x³-y³ = (x-y)(x²+xy+y²)=(x-y)*13 = 26
x-y = 26/13 = 2
x = y+2
(y+2)²+(y+2)y+y²=13
y²+4y+4+y²+2y+y² = 13
3y²+6y-9 = 0
y²+2y-3 = 0
(y-1)(y+3) = 0
y₁ = 1, x₁= 3
y₂ = -3, x₂=-1
x- cкорость течения
44/(20+x) + 54/(20-x) = 7-2
44(20-x) + 54(20+x)=5(400-x^2)
880 - 44x + 1080 + 54x = 2000 - 5x^2
1960 + 10x = 2000 - 5x^2
5x^2 + 10x - 40 = 0
x^2 + 2x - 8 = 0
x1 = 2 x2=-4
Ответ: 2 км/ч