1) b (квадрат)-0,36= (b-0,6)*(b+0,6)
2) у (квадрат)- 6у+9 = (y-3)*(y-3)
АС/АВ=cosA, AC/5=0,8 , AC=5*0,8=4,
BC²=AB²-AC²=25-16=9, BC=3
<span>3⁵ˣ⁺¹²=81ˣ
</span>
<span>3⁵ˣ⁺¹²=3⁴ˣ
</span><span>
</span><span>5х+12=4х
</span><span>
</span><span>х=-12
</span>
F(x)=4x+2x²-x³ [0;3]
f`(x)=4-4x-3x²=0
3x²+4x-4=0 D=64
x=2/3 x=-2 ∉ [0;3]
f(0)=4*0+2*0²-0³=0
f(2/3)=4*(2/3)+2*(2/3)²-(2/3)³=8/3+8/9-8/27=(8*9+8*3-8)/27=
=(72+24-8)/27=88/27=3⁷/₂₇=max
f(3)=4*3+2*3²-3³=12+18-27=3