Промежуток пренадлежит числу 7
<span>а) 24-x^2=0
x²=24
x=-2√6 U x=2√6
б) 81x^2=100</span>
x²=100/81
x=-10/9 U x=10/9
<span>(x+4)^2=3x+40
x²+8x+16-3x-40=0
x²+5x-24=0
x1+x2=-5 U x1*x2=-24
x1=-8 U x2=3
x^2+3x/2=x+7/4</span>
x²+3x/2-x-7/4=0
4x²+2x-7=0
D=4+112=116
x1=(-2-2√29)/8=-(1+√29)/4
x2=-(1-√29)/4
<span>F(x)=x^3-3x+15
1. f(x)`=3x^2-3
2. f(x)``=6x
3. f(x)```=6</span>
1. -6х+9х=-5+23
-3х=18
х=-6
2. 8х-6=5х+3
8х-5х=3+6
3х=9
х=3
3. 6х+7=20х-5-16
6х-20х=-5-16-7
-14х=-28
х=2
4. 15х-12х-20=14х+35
15х-12х-14х=35+20
-11х=55
х=-5
5. 15х-40-6+15х=4х-20
15х+15х-4х=-20+40+6
26х=26
х=1
6. 2х-46+45-3х=-х+1
2х-3х+х=1+46-45
0х=2
х=0