<span><u>x^3-x+2</u> =<u> x(x^2-1)+2</u> = <u> x(x^2-1)</u> + <u> 2 </u> = x + <u> 2 </u></span>
3/10 + 7/6 : 5/3 = 3/10 + 7/6 * 3/5 = 3/10 + 7/2 * 1/5 = 3/10 + 7/10 = 10/10 = 1
(1+cos2a)²/4 +(1-cos2a)*(1+cos2a)/4=(1+2cos2a+cos²2a+1-cos²2a)/4=
=2(1+cos2a)/4=(sin²a+cos²a+cos²a-sin²a)/2=2cos²a/2=cos²a
ОДЗ х(10-х)>=0
{ x>=0
{10-x>=0 x<=10 0<=x<=10
{x<=0
{10-x<=0 x>=10 пустое мн-во
в итоге ОДЗ 0<=x<=10
y`=(5-x)/(√10x-x^2)
y`=0 x=5
y(мах)=y(5)=5
y(мин)=y(0)=y(10)=0