1)3ab-7ac=a(3b-7c)
2)6b³-3b=3b(2b²-3)
3)9x²-y²=(3x)²-y²=(3x+y)(3x-y)
<span>2cos²x-1=-1/2
</span><span>2cos²x=1-1/2
</span><span>2cos²x=1/2
</span><span>cos²x=1/4
</span>cos²x-1/4=0
(cosx-1\2)(cosx+1\2)=0
cosx-1\2=0 или cosx+1\2=0
cosx=1\2 cosx=-1\2
x=
+2πn x=2\3π+2πk
-2sin2xcos5x-√3sin2x=0
-sin2x(2cos5x+√3)=0
sin2x=0⇒2x=πn⇒x=πn/2
cos5x=-√3/2
5x=+-5π/6+2πn⇒x=+-π/6+2πn/5