Решение
<span>1 ) х </span>²<span> - 16 < 0
x</span>² - 16 = 0
<span>x</span>² = 16
<span>x</span>₁ = - 4
<span>x</span>₂ = 4
<span>- 4 < x < 4
2) х</span>² <span>- 95 < 0
x</span>² - 95 = 0
<span>x</span>² = 95
<span>x</span>₁ = - √95
<span>x</span>₂ = √95
<span>- </span>√95 < x < √95
<span>
3) х</span>²<span> + 1 > 0
x </span>∈ R
<span>2*3(х+1), это степень)-3х=15</span>
<span>2*3^(x+1)-3^x=15</span>
<span>2*3^x*3-3^x=15</span>
<span>6*3^x-3^x=15</span>
<span>5*3^x=15</span>
<span>3^x=3^1</span>
<span>x=1</span>
2-
3-
<span>
</span>
7х+4у=10
2х+3у=1
х= (1-3у)/2
7*(1-3у)/2 + 4у = 10
7 - 21у + 8у = 20
-13у = 20-7
-13у = 13
у = -1
х = (1-3у)/2 = (1-3*(-1))/2 = (1+3)/2=4/2=2
Ответ: (2; −1)