H2S+2LiOH=Li2S+2H2O
n(LiOH)=22моль
n(H2S)=22моль×2=44моль
Читай))0)) ну кроме осадка еще нитрат натрия получим
А) Mg + 2HBr = <span>H2</span> + <span>MgBr2</span>BAO<span> + </span>2<span>HNO3</span><span> = </span><span>BA(NO3)2</span><span> + </span><span>H2O
</span>2NaOH<span> + </span><span>H2S</span><span> = </span><span>Na2S</span><span> + </span>2<span>H2O</span>
б) 2<span>Li2O</span> + 7<span>H2SO4</span> = 4<span>LiO4</span> + 7<span>SO2</span> + 7<span>H<span>2
</span></span>Fe(OH)2<span>+ </span>2<span>HNO3</span><span> = </span><span>Fe(NO3)2</span><span> + </span>2<span>H2O
</span>3<span>K2SiO3</span><span> + </span>2<span>H3PO4</span><span> = </span>2<span>K3PO4</span><span> + </span>3<span>H2SiO<span>3</span></span>
<span>Рассчитайте объем углекислого газа (н.у) , полученного при сгорании 160 г метанола </span>
<span>160г--------------------Хл </span>
<span>2СН3ОН+3О2===2СО2+4Н2О </span>
<span>64г----------------------44,8 </span>
<span>Х=112(л) это ответ. </span>