формулы в фото
2)
Дано:
m(C₂H₆)=90 г
О₂
m(H₂O)-?
Решение:
90 г ------------------------- х г
2С₂H₆ + 7O₂ = 4CO₂ + 6H₂O
60 г ------------------------ 108 г
х = 90 г*108 г\60г = 162 г
<span>6K + N2 ---> 2K3N</span>
3Ba + 2O2 ---> 2BaO + BaO2
<span>2Al + 3NiSO4 ---> 3Ni +Al2(SO4)3
</span>
<span><span>BaO + 2HCl (разб.) ---> BaCl</span>2<span> + H</span>2<span>O </span></span>
<span><span>BaO + 2Н(+) + 2Сl(-) ----> Ba(2+)+ 2Cl(-) + H2O </span></span>
<span><span><span>3Ba(OH)2 + 2AlCl3 ---> 2Al(OH)3 + 3BaCl2
</span></span></span>
<span><span><span><span>3KOH+ CrCl3 + ---> Cr(OH)3↓ + 3KCl</span></span></span></span>
<span><span><span><span>3K (+) + 3OH(-) + Cr (3+) + 3Cl(-) ---> Cr(OH)3↓ + 3K (+)+ 3Cl(-)</span></span></span></span>
<span><span><span><span> 3OH(-) + Cr (3+)---> Cr(OH)3↓</span></span></span></span>
<span><span><span><span><span>Al</span>2<span>O</span>3<span> + 2NaOH ---> 2NaAlO</span>2<span> + H</span>2<span>O (при сплавлении)</span></span></span></span></span>
<span><span><span><span><span><span>2Al(ОН)3+3H2SO4 = Al2(SO4)3+6H2O
</span></span></span></span></span></span>
<span> 53г хл
2HCl+Na2CO3 = 2NaCl + CO2+H2O
106г 22,4л
х= 53*22,4/106= 11,2л
n(CO2)=V/Vm=11.2л/22,4л/моль=0,5моль</span>