Мы сегодня писали контрольную с таким же 3 номером)
Ответ:
6CO2 + 6H2O => C6H12O6 + 6O2
C6H12O6 => 2C2H5OH + 2CO2
CH3COOH + HOC2H5 => CH3C(=O)-O-C2H5 + H2O
CH3C(=O)-O-C2H5 + H2O => CH3COOH + C2H5OH
2CH3COOH + Mg => (CH3COO)₂Mg + H₂
Mr( PbS ) = Ar(Pb) + Ar(S) = 85 + 32 = 117
Mr( CaSO3) = Ar(Ca) + Ar(S) +3× Ar(O) = 40+32+3×16=72+48=120
Mr( Mg(OH)2) = Ar(Mg) + 2×(Ar(O)+Ar(H))= 24+2×(16+1)= 24+34=58
Mr( Ca3(PO4)2) = 3×Ar(Ca)+2×(Ar(P)+4×Ar(O)) = 3×40+2×(31+4×16) = 120+128 = 248
Mr(Fe2(SO4)3 = 2×Ar(Fe)+3×(Ar(S)+4×Ar(O)) = 2×56+3×(32+4×16) = 112+3×96 = 112+288 = 400
1)провести дегидрирование с3н6=>с3н4+н2
<span>2) 2 C3H4 + 2 Na = 2 C3H3Na + H2
</span>3) C3H3Na+CН3Br=C4H6+NaBr
4) <span>C4H6 + H2O => C4H7OH
</span><span>С4H6 + 2Br2 = C4H4Br2 + 2HBr
</span><span>С4H6 + HBr = C4H5Br + H2
</span>5)<span>С4H6 + h2 = C4H8</span><span>
</span>
Я надеюсь вы все поймёте )