Cm = n/m(H₂O) = 5,88/(1335-577) = 7,76(моль/кг)
n(H₂O) = 758/18 = 42,11(моль/л)
∑n(H₂O + H₂SO₄) =5,88+42,11=47,99
Xj(H₂SO₄)=5,88/47,99=0,123
Xj(H₂O) = 1 - 0,123 = 0,877
ню (al)= 216 / 27 = 8 моль