1.2n+n=1-1, 2.2n=0, n=0/2.2, n=0
<span>а)1/8 - а³=(0,5)³-a³=(0.5-a)(0.5²+0.5a+a²)=(0.5-a)(0.25-0.5a+a²)
б)125+b³=5³+b³=(5+b)(5²+5b+b²)=</span><span>(5+b)(25+5b+b²)
в)а³+b³=(a+b)(a²-ab+b²)
г)1-64а³=1³-(4a)</span>³=(1-4a)(1²+4a+(4a)²)=(1-4a)(1+4a+16a²)
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