4P+5O2=2P2O5
n(P)=60г/31г/моль≈2 моль
n(P2O5)= (2/4)*2 моль= 1 моль
m(P2O5)= M*n=142г/моль*1 моль = 142г
1)Zn + Cl2 = ZnCl2
<span>2)ZnCl2 +2 NaOH = Zn(OH)2 + 2NaCl
3)</span><span>Zn(OH)2 + H2SO4 = ZnSO4 + 2H2O
4)</span><span>ZnSO4 + 2HNO3 = Zn(NO3)2 + H2SO4
5)Zn(NO3)2+2HBr =ZnBr2+H2O+2NO2</span>
<span>а)Ca => CaO => Ca(OH)2 => Ca(NO3)2 => CaSO4
1)2Ca+O2=2CaO
2)CaO+H2O=Ca(OH)2
3)Ca(OH)2+2HNO3=Ca(NO3)2+2H2O
4)Ca(NO3)2+H2SO4=CaSO4+2HNO3
б)</span><span>C => CO2 => Na2CO3 => CO2 => CaCO3
1)C+O2=CO2
2)</span><span>CO2 + 2NaOH = Na2CO3 + H2O
3)</span><span>Na2CO3 -> Na2O + CO2
4)CO2+H2O=H2CO3
в)</span><span>Fe2(SO4)3 => Fe(OH)3 => Fe2O3 => Fe2(SO4)3
1)Fe2(SO4)3</span><span> + 6NaOH = 3Na2SO4 + 2Fe(OH)3
2)2Fe(OH)3=Fe2O3+3H2O
3)Fe2O3+3H2SO4=Fe2(SO4)3+3H2O
г)</span><span>P => P2O5 => H3PO4 => Ca3(PO4)2 => H3PO4 => Ca(H2PO4)2
1)4P+5O2=2P2O5
2)P2O5+3H2O=2H3PO4
3)2H3PO4+3Ca(OH)2=Ca3(PO4)2+6H2O
4)</span><span>Ca3(PO4)2 + 3H2SO4 = 3CaSO4↓ + 2H3PO4
5)</span><span> 2Н3РО4 + Са (ОН) 2 = Са (Н2РО4)2+ 2Н2О </span>
Дано:
<span>N(O</span>₂<span>) = 48 ∙ 10</span>²³<span> молекул</span>
<span>Найти: V(O</span>₂<span>)</span>
Решение:
<span>M(O</span>₂<span>) = 16∙2 = 32 г\моль</span>
<span>n(O</span>₂<span>) = N\Na = </span>48 ∙ 10²³<span> <span> \</span><span>6,023 </span>∙<span> 10</span></span>²³<span><span> моль</span></span>⁻¹<span><span> = 8 моль</span></span>
<span>N(O</span>₂<span>) = Vm∙ n<span> = 22,4 л\моль </span>∙ 8 моль = 179,2 г</span>
Ответ: 179,2 л