A = 100 1001 = 2^6+2³ +1= 64+8+1 = 73 (10c/c)
B = 100 1100 = 2^6+2³+2² =64+8+4= 76 (10c/c)
73 < 75 < 76
Ответ: 2)
Это технология управления и обмена информацией между программным интерфейсом других приложений.
Program task1;
var a :integer;
begin
randomize; a:= 0; while (a <> 5) and (a <> 6) do a:= random(7); writeln(a);
<span>end.
program task2;
var Digit, i :integer; DigitStr :string;
begin
readln(Digit); str(Digit,DigitStr); for i:= length(DigitStr) downto 1 do write(DigitStr[i]);
<span>end.
program task3;
var Digit :integer; NewDigit, DigitStr :string;
begin
readln(Digit); str(Digit,DigitStr); NewDigit:= DigitStr[3] + DigitStr[4] + DigitStr[1] + DigitStr[2]; writeln(NewDigit);
<span>end.</span></span></span>
Python 3.6.1:
from random import random
N = 100
a = []
for i in range(N):
a.append(int(random()*2))
print(a[i],end=' ')
print()
for i in range(N):
if (a[i] == 0):
a[i] = 1
else:
a[i] = 0
print(a[i],end=' ')
from random import random
N = 20
a = []
for i in range(N):
a.append(int(random()*(2*N+1)-N))
print(a[i],end=' ')
Max = max(a)
Min = min(a)
print('\nMax =',Max)
print('Min =',Min)
print('Max - Min =',Max-Min)
Циклической,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,