Х²-6х+5=0 б х1+х2=6 и х1*х2=5⇒х1=1 и х2=5
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1)х<1 U x>5
-/x²-6x+5/=-x²+6x-5
2)1≤x≤5
-/x²-6x+5/=x²-6x+5
Ответ:
Объяснение:
2y/(5a) +a⁴/(2y)=(2y·2y+5a·a⁴)/(5a·2y)=(4y²+5a)/(10ay)
(3z-8)/(5z²) +(z-1)/z²=(3z-8+5(z-1))/(5z²)=(3z-8+5z-5)/(5z²)=(8z-13)/(5z²)
(2a+3b)/(21ab) +(a-6b)/(15ab)=(2a+3b)/(3·7ab) +(a-6b)/(3·5ab)=5(2a+3b)/(5·21ab) +7(a-6b)/(7·15ab)=(10a+15b+7a-42b)/(105ab)=(17a-27b)/(105ab)
2/(a-5) +5/(2a-10)=2/(a-5) +5/(2(a-5))=(2·2+5)/(2(a-5))=(4+5)/(2a-10))=9/(2a-10)
2/(a+5) +3/(a+2)=(2(a+2)+3(a+5))/((a+5)(a+2))=(2a+4+3a+15)/(a²+2a+5a+10)=(5a+19)/(a²+7a+10)
(y-x)/(x(x-a)) +(a-y)/(a(x-a))=(a(y-x)+x(a-y))/(ax(x-a))=(ay-ax+ax-xy)/(ax(x-a))=(ay-xy)/(ax(x-a))=y(a-x)/(-ax(a-x))=-y/(ax)
2b/(1-b²) +1/(1+b)=2b/((1-b)(1+b)) +1/(1+b)=(2b+1-b)/((1-b)(1+b))=(b+1)/((1-b)(b+1))=1/(1-b)
a/(a+b)² +1/(a+b)=a/((a+b)(a+b)) +1/(a+b)=(a+a+b)/(a+b)²=(2a+b)/(a+b)²=(2a+b)/(a²+2ab+b²)
Решение
Sin(3x/2 + π/12) < √2/2
- π - arcsin(√2/2) + 2πk < 3x/2 + π/12 < arcsin(√2/2) + 2πk, k ∈ Z
- π - π/4 + 2πk < 3x/2 + π/12 < π/4<span> + 2πk, k ∈ Z
</span>- 5π/4 + 2πk < 3x/2 < π/4<span> + 2πk, k ∈ Z
</span>- 5π/4 - π/12 + 2πk < 3x/2 < π/4 - π/12 + 2πk, k ∈ Z
- 4π/3 + 2πk < 3x/2 < π/6 <span>+ 2πk, k ∈ Z
</span>- 8π/3 + 4πk < 3x < π/3 <span>+ 4πk, k ∈ Z
</span>- 8π/9 + 4πk/3 < <span>x < </span>π/9 <span>+ 4πk/3, k ∈ Z</span>
1/log2 1/x > 1/log2 (3-2x)
Y=1-3x;
x^2+(1-3x)^2+x(1-3x)=3;
x^2+1-6x+9x^2-3x^2+x-3=0;
7x^2-5x-2=0;
D=81;
x1=5+9/14=1; x2=-4/14=-2/7;
y1=1-3=-2; y2=1+6/7=13/7;
Ответ: (1;-2) и (-2/7;13/7)